Answer :
wavelength = plancks constant/(mass*velocity)
plancks constant= 6.63*10^-34 with units of J-s or kg-m^2/s^2-s
mass = 143g = 0.143kg
velocity = 95mi/1hr(1609.3m/1mi)(1hr/3600sec) = 42.4676m/s
h/mv = 6.63*10^-34kg-m^2/s^2-s/(42.4676m/s*0.143kg...
wavelength = 1.3*10^-34 m (really small)
good luck! (always make sure units cancel out)
plancks constant= 6.63*10^-34 with units of J-s or kg-m^2/s^2-s
mass = 143g = 0.143kg
velocity = 95mi/1hr(1609.3m/1mi)(1hr/3600sec) = 42.4676m/s
h/mv = 6.63*10^-34kg-m^2/s^2-s/(42.4676m/s*0.143kg...
wavelength = 1.3*10^-34 m (really small)
good luck! (always make sure units cancel out)
Answer:
De-Broglie wavelength of the baseball is [tex]1.08\times 10^{-34}\ m[/tex]
Explanation:
It is given that,
Mass of the baseball, m = 143 g = 0.143 kg
Velocity of the baseball, v = 95 m/h
Converting m/h to m/s
1 m/h = 0.447 m/s
Velocity of the baseball, v = 95 m/h = 42.46 m/s
De-Broglie wavelength is given by :
[tex]\lambda=\dfrac{h}{mv}[/tex]
h is Planck's constant
[tex]\lambda=\dfrac{6.6\times 10^{-34}}{0.143\times 42.46}[/tex]
[tex]\lambda=1.08\times 10^{-34}\ m[/tex]
Hence, the De-Broglie wavelength of the baseball is [tex]1.08\times 10^{-34}\ m[/tex]