Answer :
Expression as product is :
x^3+x^2y–4y–4x = [tex](x-2)(x+2)(x+y)[/tex]
y^2(2y–5)–8y+20 = [tex](y-2)(y+2)(2y-5)[/tex]
Step-by-step explanation:
Here we need to write , following expression as product:
x^3+x^2y–4y–4x
⇒ [tex]x^3+x^2y-4y-4x[/tex]
⇒ [tex]x^2(x+y)-4y-4x[/tex]
⇒ [tex]x^2(x+y)-4(y+x)[/tex]
⇒ [tex](x^2-4)(x+y)[/tex]
⇒ [tex](x-2)(x+2)(x+y)[/tex]
y^2(2y–5)–8y+20
⇒ [tex]y^2(2y-5)-8y+20[/tex]
⇒ [tex]y^2(2y-5)-4(2)y+4(5)[/tex]
⇒ [tex]y^2(2y-5)-4(2y-5)[/tex]
⇒ [tex](y^2-4)(2y-5)[/tex]
⇒ [tex](y-2)(y+2)(2y-5)[/tex]