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7 red balls, 9 green balls, and 3 blue balls you draw two balls from the urn but replace the first ball before drawing the second find the probability that the first ball is red and the second is heee

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winterdark2

Answer:

Step-by-step explanation:

With replacement of the first ball

P(first ball is red and the second is green) =7/19 * 9/19= 63/361=.175

without replacement (14 total balls in the urn on the second draw)

P(first ball is red and the second is green) =7/18 * 9/18= 63/324=.194

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