Answer:
1. Part 1:
[tex]F_g=2.20\times 10^{-8}N[/tex]
2. Part 2:
[tex]F_g=1.28\times 10^{-6}N[/tex]
Explanation:
Part 1:
1. Data:
- Fg = ?
- m₁ = 4.80 kg
- m₂ = 15.8 kg
- d = 0.480 m
2. Formula
Newton's law of gravitational attraction:
[tex]F_g=G\dfrac{m_1\times m_2}{d^2}[/tex]
Where:
- Fg is the gravitational force between two bodies
- m₁ and m₂ are the masses of the two bodies
- d is the distance that separate the centers of the two bodies
- G is the universal constant of gravitational attraction: 6.67 10⁻¹¹ N.m²/kg²
3. Solution
Substitute the data into the formula and compute:
[tex]F_g=6.67\times 10^{-11}N\cdot m^2/kg^2\times \dfrac{4.80kg\times 15.8kg}{(0.480m)^2}[/tex]
[tex]F_g=2.20\times 10^{-8}N[/tex]
Part 2:
1. Data:
- Fg = ?
- m₁ = 4.80 kg
- d = 6.89 × 10¹¹ m
- m₂ = 1.90 × 10²⁷ kg
2. Use the same formula and use the new data:
[tex]F_g=6.67\times 10^{-11}N\cdot m^2/kg^2\times \dfrac{4.80kg\times 1.90\times10^{27}kg}{(6.89\times 10^{11}m)^2}[/tex]
[tex]F_g=1.28\times 10^{-6}N[/tex]
