Step-by-step explanation:
Given:
[tex] (2,\:0)=(x_1,\:y_1) \:\&\: m = - \frac{4}{5}[/tex]
Equation of line in slope point form is given as=
[tex]y - y_1 = m(x-x_1) \\ \therefore \: y - 0 = - \frac{4}{5}(x - 2) \\ \therefore \: y = - \frac{4}{5}(x - 2) \\ \therefore \: 5y = - 4(x - 2) \\ \therefore \: 5y = - 4x + 8 \\ \therefore \: 5y + 4x - 8 = 0 \\\therefore \: 4x + 5y - 8 = 0 \\ which \: is \: the \:equation \:of \: required \: \\ line.\: [/tex]
