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At one particular moment, a 15.0 kg toboggan is moving over a horizontal surface of snow at 4.40 m/s. After 7.50 s have elapsed, the toboggan stops. Use a momentum approach to find the magnitude of the average friction force (in N) acting on the toboggan while it was moving.

Answer :

xero099

Answer:

[tex]f = 8.8\,N[/tex]

Explanation:

The moment equation of the toboggan is:

[tex]m_{t}\cdot v_{o} - f\cdot \Delta t = 0[/tex]

The average friction force is:

[tex]f=\frac{m_{t}\cdot v_{o}}{\Delta t}[/tex]

[tex]f = \frac{(15.0\,kg)\cdot (4.40\,\frac{m}{s} )}{7.50\,s}[/tex]

[tex]f = 8.8\,N[/tex]

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