Answer :
Answer:
P-value = 0.019
Step-by-step explanation:
We are given ;
Null Hypothesis, [tex]H_0[/tex] : μ = 130
Alternate Hypothesis, [tex]H_1[/tex] : μ > 130
Also, the test statistics (t) is given to us as 2.33 and degree of freedom as 14.
P-value is given by = P([tex]t_1_4[/tex] > 2.33) = 0.019 or 1.9% .
Therefore, the appropriate p-value is 0.019 .