Answer :
Answer:
[tex]I = 14.12 W/m^2[/tex]
Explanation:
Given that:
acoustic power (P)= 3.77 × 10⁵ W
Find the intensity of the sound at a distance of 46.1 m from the engine
The distance (i.e the radius) = 46.1 m
The relation [tex]I=\frac{P}{4 \pi r^2}[/tex] can used to find the intensity of the sound from the engine.
Substituting our values, we have:
[tex]I= \frac{3.77*10^5}{4 \pi (46.1)^2}W/m^2[/tex]
[tex]I = 14.117 W/m^2[/tex]
[tex]I = 14.12 W/m^2[/tex]
The intensity of the sound at the given distance is 14.11 W/m².
The given parameters;
- power of the jet engine, P = 3.77 x 10⁻⁵ W.
- distance of the sound, r = 46.1 m
The intensity of the sound at the given distance is calculated as follows;
[tex]I = \frac{P}{A}[/tex]
where;
- I is the intensity of the sound
- P is the power
- A is the area of the surrounding
[tex]\\\\I = \frac{P}{4\pi r^2} \\\\I = \frac{3.77 \times 10^5}{4\pi (46.1)^2} \\\\I = 14.11 \ W/m^2[/tex]
Thus, the intensity of the sound at the given distance is 14.11 W/m².
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