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A sample of solid ammonium chloride was placed into an evacuated rigid container and then heated so that it decomposed to ammonia gas and hydrogen chloride gas. After heating the total pressure in the container was found to be 4.4 atm. Calculate Kp at this temperature for the decomposition reaction

Answer :

Giangiglia

Answer:

[tex]Kp=4.84 atm^2[/tex]

Explanation:

The reaction

[tex]NH_4Cl \longrightarrow NH_3 + HCl[/tex]

Given that the mole rate of NH3 and HCl is 1:1 their concentrations in the gas are equal:

[tex]y_{NH_3}=y_{HCl}=0.5[/tex]

Following Dalton's law:

[tex]P_{NH_3}=y_{NH3}*P=0.5*4.4 atm= 2.2 atm[/tex]

[tex]P_{HCl}=y_{HCl}*P=0.5*4.4 atm= 2.2 atm[/tex]

The Kp

[tex]Kp=P_{HCl}*P_{NH_3}=(2.2atm)*(2.2atm)[/tex]

[tex]Kp=4.84 atm^2[/tex]

Note: the ammonium chloride isnt in the Kp given that it's in solid state.

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