Answer :
Answer:
[tex]<0,-8.32\times 10^{-17},0>N[/tex]
Explanation:
We are given that
Electric field at a particular location=[tex]<0,-260,0>N/C[/tex]
Charge on alpha particle,q=2e
Charge on alpha particle,q=[tex]2\times 1.6\times 10^{-19}=3.2\times 10^{-19}C[/tex]
Where 1 e=[tex]1.6\times 10^{-19}C[/tex]
Force on alpha particle=qE
Where q= Charge on particle
E=Electric field
Using the formula
Force on alpha particle=[tex]3.2\times<0,-260,0>[/tex]
Force on alpha particle=[tex]<0,-8.32\times10^{-17},0>N[/tex]
Hence, the force at this particular location=[tex]<0,-8.32\times 10^{-17},0>N[/tex]