Answer:
[tex]-2.00876\times 10^{-18}\ J[/tex]
Explanation:
v = Speed of electron = [tex]2.1\times 10^6\ m/s[/tex] (generally the order of magnitude is 6)
m = Mass of electron = [tex]9.11\times 10^{-31}\ kg[/tex]
Work done would be done by
[tex]W=K_i-K_f\\\Rightarrow W=0-\dfrac{1}{2}mv^2\\\Rightarrow W=0-\dfrac{1}{2}\times 9.11\times 10^{-31}\times (2.1\times 10^6)^2\\\Rightarrow W=-2.00876\times 10^{-18}\ J[/tex]
The work required to stop the electron is [tex]-2.00876\times 10^{-18}\ J[/tex]
