Answered

Evaluate (1/3+1/4+...+1/2009)(1+1/2+...+1/2008)-(1+1/3+1/4+...+1/2009)(1/2+1/3+...+1/2008)

Answer :

Answer:

-2007/4018

Step-by-step explanation:

1. Given

(1/3+1/4+...+1/2009)(1+1/2+...1/2008) - (1+1/3+1/4+...+1/2009)(1/2+1/3+...+1/2008)

2. Set new variable

k = 1/3+1/4+...+1/2008

3. Rewrite the equation

(k+1/2009)(1+1/2+k) - (1+k+1/2009)(1/2+k)

4. Simplify

(k+1/2009)(k+3/2) - (k+2010/2009)(k+1/2)

5. Expand

[k^2 + (1/2009 + 3/2)k + (1/2009)(3/2)] - [k^2 - (2010/2009+1/2)k - (2010/2009)(1/2)]

6. Rewrite

(1/2009 + 3/2 - 2010/2009 - 1/2)k + (1/2009)(3/2) - (2010/2009)(1/2)

7. Simplify

(3/2 - 2009/2009 - 1/2)k + 1/2(3/2009-2010/2009)

8. Evaluate

0*k + 1/2(-2007/2009)

= -2007/4018

The solution of the expression  (1/3+1/4+...+1/2009)(1+1/2+...+1/2008)-(1+1/3+1/4+...+1/2009)(1/2+1/3+...+1/2008) is  -2007/4018.

What is expression?

An expression is a combination of numbers, symbols or variables that have coefficients.

How to evaluate expression?

We have to evaluate the expression:

(1/3+1/4+...+1/2009)(1+1/2+...1/2008) - (1+1/3+1/4+...+1/2009)(1/2+1/3+...+1/2008)

Set new variable , k = 1/3+1/4+...+1/2008

Rewrite the equation

(k+1/2009)(1+1/2+k) - (1+k+1/2009)(1/2+k)

Simplify the equation:

(k+1/2009)(k+3/2) - (k+2010/2009)(k+1/2)

Expand

[k^2 + (1/2009 + 3/2)k + (1/2009)(3/2)] - [k^2 - (2010/2009+1/2)k - (2010/2009)(1/2)]

Rewrite

(1/2009 + 3/2 - 2010/2009 - 1/2)k + (1/2009)(3/2) - (2010/2009)(1/2)

Simplify

(3/2 - 2009/2009 - 1/2)k + 1/2(3/2009-2010/2009)

Evaluate

0*k + 1/2(-2007/2009)

= -2007/4018

Hence the solution of expression is -2007/4018.

Learn more about expression at https://brainly.com/question/723406

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