Answer :
Answer:
Vc = 2.41 v
Explanation:
voltage (v) = 16 v
find the voltage between the ends of the copper rods .
applying the voltage divider theorem
Vc = V x ([tex]\frac{Rc}{Rc + Ri}[/tex])
where
- Rc = resistance of copper = [tex]\frac{ρl}{a}[/tex] (l = length , a = area, ρ = resistivity of copper)
- Ri = resistance of iron = [tex]\frac{ρ₀l}{a}[/tex] (l = length , a = area, ρ₀ = resistivity of copper)
Vc = V x ([tex]\frac{\frac{ρl}{a}}{\frac{ρl}{a} + \frac{ρ₀l}{a}}[/tex])
Vc = V x ([tex]\frac{ρ x (\frac{l}{a})}{(ρ + ρ₀) x (\frac{l}{a})}[/tex])
Vc = V x ([tex]\frac{ρ}{ρ + ρ₀}[/tex])
where
- ρ = resistivity of copper = 1.72 x 10^{-8} ohm.meter
- ρ₀ = resistivity of iron = 9.71 x 10^{-8} ohm.meter
Vc = 16 x ([tex]\frac{1.72 x 10^{-8}}{1.72 x 10^{-8} + 9.71 x 10^{-8}}[/tex])
Vc = 2.41 v