someone solve these equations with working really appreciate it


Answer:
a) [tex]t = \sqrt{\frac{d}{4.9} }[/tex]
b) t = 0.3 seconds
c) d = 4.9t²
d) d = 11 cm.
Step-by-step explanation:
One test involves catching a 1 m ruler and measuring the distance, d in meters, that the ruler will travel before being caught, the reaction time t in seconds is then calculated using the formula
[tex]t = \sqrt{\frac{2d}{9.8} }[/tex] .......... (1)
a) the simplified expression is
[tex]t = \sqrt{\frac{d}{4.9} }[/tex] ......... (2)
b) If d = 44 cm = 0.44 meters, from equation (2) we get,
t = 0.299 seconds ≈ 0.3 seconds (Approximate)
c) If we make d as the subject of the equation, then
[tex]t^{2} = \frac{d}{4.9}[/tex]
⇒ d = 4.9t² .......... (3)
d) Now, if [tex]t = \frac{0.3}{2} = 0.15[/tex] seconds, then from equation (3) we get,
d = 4.9 (0.15)² = 0.11 meters = 11 cm (Answer)