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A student wants to prepare a solution of cobalt(II) fluoride with a known molarity.
How many grams of CoF2 must be weighed out to prepare 100. mL of a 0.157 M aqueous solution of the salt?
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Answer :

znk

Answer:

[tex]\large \boxed{\text{1.52 g}}[/tex]

Explanation:

1. Calculate the moles of CoF₂ needed

[tex]n = \text{0.100 L} \times \dfrac{\text{0.157 mol}}{\text{1 L}}  = \text{0.0157 mol}[/tex]

2. Calculate the mass of CoF₂

[tex]m = \text{0.0157 mol} \times \dfrac{\text{96.93 g}}{\text{1 mol}}  = \text{1.52 g}\\\\\text{ The student must measure out $\large \boxed{\textbf{1.52 g}}$ of cobalt(II) fluoride}[/tex]

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