Answer:
10 square inches.
Step-by-step explanation:
The area [tex]A[/tex] of a trapezoidal package with bigger base [tex]b[/tex], height [tex]h[/tex], and smaller base [tex]a[/tex], is
[tex]A=\frac{a+b}{2}*h[/tex].
In our case
[tex]b=12[/tex]
[tex]h=10[/tex]
[tex]a=10[/tex]
therefore we have
[tex]A_t = \frac{12+10}{2}*10=110 \:in^2[/tex]
the area of the trapezoid is 110 square inches.
Now, the area [tex]A_r[/tex] of the rectangular package is its length times height
[tex]A_r=12in*10in=120\:in^2[/tex]
the area of the rectangle is 120 square inches.
The difference in area between the two packages is
[tex]120\:in^2-110\:in^2=10\:in^2[/tex]
10 square inches.