Answer:
Option B. [tex]P=\frac{3}{5}[/tex]
Step-by-step explanation:
we know that
The probability of an event is the ratio of the size of the event space to the size of the sample space.
The size of the sample space is the total number of possible outcomes
The event space is the number of outcomes in the event you are interested in.
so
Let
x------> size of the event space
y-----> size of the sample space
so
[tex]P=\frac{x}{y}[/tex]
In this problem we have
odd number are the cards ----> 1,3,5,7,9,11,13, and 15 (total 8 cards)
so
1) the probability that you choose an odd number is
[tex]x=8[/tex]
[tex]y=15[/tex]
substitute
[tex]P=\frac{8}{15}[/tex]
2) the probability that you choose a two is
[tex]x=1[/tex]
[tex]y=15[/tex]
substitute
[tex]P=\frac{1}{15}[/tex]
3) the probability that you choose an odd number or a two is
Sum the probabilities
[tex]P=\frac{8}{15}+\frac{1}{15}=\frac{9}{15}[/tex]
Simplify
[tex]P=\frac{3}{5}[/tex]
