[tex] \sin(90) + \cos(45 ) = [/tex]
![[tex] \sin(90) + \cos(45 ) = [/tex] class=](https://us-static.z-dn.net/files/df5/9b6fe167db3445df433e4fb8ff26815c.jpg)
Answer:
you know that sin 90 is 1 and cos 45 is 1/√2
so,
[tex]sin90 + cos45 \\ = 1 + \frac{1}{ \sqrt{2} } \\ = \frac{ \sqrt{2} + 1 }{2} [/tex]