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A force is applied with a magnitude of 70 N at an angle of 50 degrees from the horizontal. What are the horizontal and vertical components of force?

Answer :

Karabo99

Answer:

Fy = 53.62 N

Fx ≈ 50 N

Explanation:

let Fx be the horizontal component of the applied force and Fy be the vertical component of the applied force then:

Fy = F×sin(∅)

    = (70)×sin(50°)

    =  53.62 N

Fx = F×cos(∅)

    = (70)×cos(50°)

    ≈ 50 N

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