Answer :
Answer :
(a) The number of sulfur atoms are, [tex]31.61\times 10^{23}[/tex].
(b) The mass of the mass of [tex]Fe_2(SO_4)_3[/tex] is, 1059.682 grams.
(c) The number of moles of [tex]Fe_2(SO_4)_3[/tex] is, [tex]8.63\times 10^{-3}mole[/tex]
(d) The mass of the mass of [tex]Fe_2(SO_4)_3[/tex] is, [tex]19.95\times 10^{-22}g[/tex]
Explanation :
(a) As we are given the number of moles of [tex]Fe_2(SO_4)_3[/tex] is, 1.75 mole. Now we have to calculate the number of sulfur atoms.
In the [tex]Fe_2(SO_4)_3[/tex], there are 2 iron atoms, 3 sulfur atoms, 12 oxygen atoms.
As, 1 mole of [tex]Fe_2(SO_4)_3[/tex] contains [tex]3\times 6.022\times 10^{23}[/tex] number of sulfur atoms.
So, 1.75 mole of [tex]Fe_2(SO_4)_3[/tex] contains [tex]1.75\times 3\times 6.022\times 10^{23}=31.61\times 10^{23}[/tex] number of sulfur atoms.
The number of sulfur atoms are, [tex]31.61\times 10^{23}[/tex]
(b) As we are given the number of moles of [tex]Fe_2(SO_4)_3[/tex] is, 2.65 mole. Now we have to calculate the mass of [tex]Fe_2(SO_4)_3[/tex].
[tex]\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3[/tex]
The molar mass of [tex]Fe_2(SO_4)_3[/tex] = 399.88 g/mole
[tex]\text{Mass of }Fe_2(SO_4)_3=2.65mole\times 399.88g/mole=1059.682g[/tex]
The mass of the mass of [tex]Fe_2(SO_4)_3[/tex] is, 1059.682 grams.
(c) As we are given the mass of [tex]Fe_2(SO_4)_3[/tex] is, 3.45 grams. Now we have to calculate the moles of [tex]Fe_2(SO_4)_3[/tex].
[tex]\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3[/tex]
The molar mass of [tex]Fe_2(SO_4)_3[/tex] = 399.88 g/mole
[tex]3.45g=\text{Moles of }Fe_2(SO_4)_3\times 399.88g/mole[/tex]
[tex]\text{Moles of }Fe_2(SO_4)_3=8.63\times 10^{-3}mole[/tex]
The number of moles of [tex]Fe_2(SO_4)_3[/tex] is, [tex]8.63\times 10^{-3}mole[/tex]
(d) As we are given the formula unit of [tex]Fe_2(SO_4)_3[/tex] is, 3. Now we have to calculate the mass of [tex]Fe_2(SO_4)_3[/tex].
As we know that 1 mole of [tex]Fe_2(SO_4)_3[/tex] contains [tex]6.022\times 10^{23}[/tex] formula unit.
Formula used :
[tex]\text{Formula unit of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times 6.022\times 10^{23}[/tex]
[tex]3=\text{Moles of }Fe_2(SO_4)_3\times 6.022\times 10^{23}[/tex]
[tex]\text{Moles of }Fe_2(SO_4)_3=4.989\times 10^{-24}mole[/tex]
Now we have to calculate the mass of [tex]Fe_2(SO_4)_3[/tex].
[tex]\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3[/tex]
The molar mass of [tex]Fe_2(SO_4)_3[/tex] = 399.88 g/mole
[tex]\text{Mass of }Fe_2(SO_4)_3=4.989\times 10^{-24}mole\times 399.88g/mole=19.95\times 10^{-22}g[/tex]
The mass of the mass of [tex]Fe_2(SO_4)_3[/tex] is, [tex]19.95\times 10^{-22}g[/tex]