Answer :
Answer:
a) Magnitude of the average velocity from t = 0 to t = 2 s = 2.24 m/s
b) Magnitude of the average velocity from t = 0 to t = 5 s = 3.16 m/s
Explanation:
a) Velocity is rate of change of position.
A particle's position coordinates (x, y) are (1.0 m, 3.0 m) at t = 0
A particle's position coordinates (x, y) are (5.0 m, 5.0 m) at t = 2.0 s
Displacement = (5-1)i + (5-3)j = 4i + 2j
Change in time = 2s
Velocity
[tex]v=\frac{4i+2j}{2}=2i+j[/tex]
Magnitude of velocity
[tex]v=\sqrt{2^2+1^2}=2.24m/s[/tex]
b) Velocity is rate of change of position.
A particle's position coordinates (x, y) are (1.0 m, 3.0 m) at t = 0
A particle's position coordinates (x, y) are (14.0 m, 12.0 m) at t = 5.0 s
Displacement = (14-1)i + (12-3)j = 13i + 9j
Change in time = 5s
Velocity
[tex]v=\frac{13i+9j}{5}=2.6i+1.8j[/tex]
Magnitude of velocity
[tex]v=\sqrt{2.6^2+1.8^2}=3.16m/s[/tex]