Answer:
The width = 6k^2 m and the length = 5k + 1 m.
Step-by-step explanation:
The GCF of 30k^3 and 6k^2 is 6k^2.
Width = 6k^2 (answer).
The length = area / width
= (30k^3 + 6k^2) / 6k^2
= 5k + 1 (answer).
The length and width of the rectangle include 5k+1 and 6k² respectively.
The area of a rectangle is given as:
= Length × Width
The area here is 30k³ +6k² m²
Since the width of the rectangle is equal to the greatest common monomial factor of 30k³ and 6k², therefore the width is 6k².
Then, the length of the rectangle will be: = (30k³ +6k²) / 6k² = 5k+1
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